Page 208 - 捷運工程叢書 精進版 - 32 捷運高架橋梁結構設計與施工
P. 208

臺北市政府捷運工程局







            一、長時

                 軸力 P = 164t
                 彎矩 M = 394.5t-m

                 剪力 V =(P×Kh)=(164×0.253)= 41.5t
                 假設外力皆由銲接承受:
                 銲接長度 L = 2πr = 2π×82.5 = 518.1cm

                            1       1
                                              2
                                 2
                                                             3
                                                   3
                 慣性矩 I =      Ar  =   (2πr)r = πr  = π×82.5  = 1,763,159.063cm  3
                            2       2
                 fb = My/I =(39,450×82.5)/(1,763,159.063)= 1.8459t/cm
                 fv = V/L =(41.5)/(518.1)= 0.08t/cm    2
                 fc = P/L =(164)/(518.1)= 0.3165t/cm    2
                 fc 是以保守考慮,上下鋼板間因施工不當而有空隙產生,無接觸,全部壓力由銲接承受
                 fr = sqr(fb^2 + fv^2 + fc^2)= 1.8745t/cm

                 採用 E70 焊條 Fu =70ksi = 4.9t/cm^2
                 銲接尺寸 S = 3.6cm

                 銲接容許應力 Fv = 0.27Fu = 0.27×70ksi = 18.9ksi = 1.323t/cm      2
                 R= 0.707×S×Fv = 0.707×3.6×1.323 = 3.367t/cm > fr ﹤ OK)
                 F.S= R / fr = 3.367 / 1.8745 = 1.796

            二、極限階段

                 ( 一 ) Case 1(假設有一部列車通過)
                           軸力 P = 72.5t
                           塑性剪力 Vp = 236.99t

                           彎矩 M = Vp×2m = 473.98t-m
                           銲接長度 L = 2πr = 2π×82.5 = 518.1cm
                           fb = My/I =(47,398×82.5)/(1,763,159.063)= 2.217t/cm

                           fv = V/L =(236.99)/(518.1)= 0.457t/cm     2
                           fc = P/L =(72.5)/(518.1)= 0.14t/cm    2
                           fr = sqr(fb^2+fv^2+fc^2)= 2.268t/cm

                           採用 E70 焊條 Fu = 70ksi = 4.9t/cm^2
                           銲接尺寸 S = 3.6cm

                           銲接容許應力 Fv = 0.27Fu = 0.27×70ksi = 18.9ksi = 1.323t/cm      2
                           R = 0.707×S×Fv = 0.707×3.6×1.323 = 3.367t/cm > fr ﹤ OK >
                           F.S = R / fr =3.367 / 2.268 = 1.48

                 ( 二 ) Case 2
                           考量極限階段時,接合處不可崩塌,故設置一 300t 之鋼質剪力榫。






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